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## Proof: (related to "Common Points of a Plane and a Straight Line Not in the Plane")

• By hypothesis, let $\alpha$ be a plane and $g$ be a straight line that is not in $\alpha.$
• If there is no point $A,$ that lies on both, $g$ and $\alpha$ then there is nothing left to be proven.
• Therefore, let $A$ lie on both, $g$ and $\alpha.$
• Assume, there is another point $B\neq A$ that also lies on both, $g$ and $\alpha.$
• By assumption and 6th axiom of connection, $g$ would be in $\alpha,$ contradicting the hypothesis.
• Therefore, there is at most one point $A,$ that lies on both.
q.e.d

| | | | created: 2019-12-26 12:19:48 | modified: 2019-12-26 12:22:33 | by: bookofproofs | references: [8324]

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