The proceeding propositions show that there are quite a lot of functions which are Riemann integrable. A question arises if there are any functions that are not. The following function $f:[0,1]\to\mathbb R$ is an example of a non-Riemann-itegrable function.

$$f(x):=\begin{cases}1&\text{if }x\text{ is rational}\\0&\text{if }x\text{ is irrational}\end{cases}.$$

The function is bounded on the closed interval $[0,1].$ Howerver, the Riemann upper and lower integrals are not equal each other:

$$\int_{0~*}^{1}f(x)dx=0\quad\neq \quad \int_{0}^{1~*}f(x)dx=1.$$

| | | | created: 2020-01-09 15:50:32 | modified: 2020-01-09 15:54:33 | by: *bookofproofs* | references: [581]

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[581] **Forster Otto**: “Analysis 1, Differential- und Integralrechnung einer Veränderlichen”, Vieweg Studium, 1983