log in sign up
logo

Proof

deleteeditadd to favorites[id:722]   
vote:
last edited 0 min ago by bookofproofs


1a) Let \(Y\in X\cup\{X\}\). We have to show that \(Y\subseteq X\cup\{X\}\), if \(X\) is a transitive set. It follows
\[Y\in X\cup\{X\}\Longrightarrow\cases{
Y=X\overset{\text{trivially}}{\Longrightarrow} Y\subseteq X\\
\text{or}\\
Y\in X\overset{X\text{ is transitive}}{\Longrightarrow} Y\subseteq X
}
\]
Altogether, it follows that \(Y\subseteq X\cup\{X\}\).

1b) Let \(Y\in \mathcal P(X)\). We have to show that \(Y\subseteq \mathcal P(X)\), if \(X\) is a transitive set. Since \(Y\in \mathcal P(X)\), it follows from the definitions of the power set that \(Y\subseteq X\). This means that for all elements \(Y^\prime\in Y\) it is also \(Y^\prime\in X\) and, because of its transitivity \(Y^\prime \subseteq X\). Now it follows from the definition of power set again that \(Y^\prime \subseteq \mathcal P(X)\).

2a) Let \(Y\in \bigcup X\). We have to show that \(Y\subseteq \bigcup X\), if \(X\) is a set of transitive sets. \(Y\in \bigcup X\) means that \(Y\) is the element of the union of all elements \(Z\in X\), i.e. \(Y\in Z\) for at least of one such \(Z\). Because of the transitivity of \(Z\) it is \(Y\subseteq Z\) and so \(Y\subseteq \bigcup X\).

2b) Let \(Y\in \bigcap X\). We have to show that \(Y\subseteq \bigcap X\), if \(X\) is a set of transitive sets. \(Y\in \bigcap X\) means that \(Y\) is the element of all elements \(Z\in X\), i.e. \(Y\in Z\) for all \(Z\in X\). Because each such \(Z\) it transitive, it follows \(Y\subseteq Z\) for all \(Z\) and so \(Y\subseteq \bigcap X\).

q.e.d

References

[656] Hoffmann, Dirk W.: “Grenzen der Mathematik - Eine Reise durch die Kerngebiete der mathematischen Logik”, Spektrum Akademischer Verlag, 2011

Contribute to BoP:

add a new Open Problem  add

add a new Comment (Branch)  add


Terms of Use | Privacy Policy | Imprint | This site is a private offer. All rights reserved.
The contents of book of proofs are licensed under the Creative Commons Attribution-ShareAlike 3.0 Unported License.