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## Proof: (related to "Convergent Real Sequences Are Cauchy Sequences")

• By hypothesis, a given real sequence $(a_n)_{n\in\mathbb N}$ is convergent to the limit $a\in\mathbb R.$
• This means that for a given $\epsilon > 0$ there is an index $N\in\mathbb N$ such that $$|a_n-a| < \frac{\epsilon}2$$ for all $n\ge N.$
• Thus, by the triangle inequality \begin{align}|a_n- a_m|&=|a_n-a+a-a_m|\nonumber\\ &\le |a_n-a|+|a-a_m|\nonumber\\ &\le \frac{\epsilon}{2}+\frac{\epsilon}{2}\nonumber\\ &=\epsilon\nonumber\end{align} for all $n,m\ge N.$
• It follows that $(a_n)_{n\in\mathbb N}$ is a real Cauchy sequence.
q.e.d

| | | | created: 2020-07-11 16:01:49 | modified: 2020-07-11 16:02:10 | by: | references: [581]