Theorem: Isomorphism of Rings 

Let $(R, + ,\cdot)$ and $(S,\ast,\circ)$ be two rings and $f:R\to S$ a ring homomorphism. Then the function $$g:R/\ker{(f)}\to\operatorname{im}(f),\quad $g([x])=f(x)$ a an isomorphism, called a ring isomorphism.

| | | | | created: 2014-02-20 23:22:18 | modified: 2019-08-11 12:47:24 | by: bookofproofs